form php code

faisal evers · #1 05-01-2008, 09:21 AM

hi ,

i'v got a problem i made a form but when i wanted to make the thank you page the php code im suppose to copy, and place my email there is not visable all i see is,
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>thank you</title>
<meta name="GENERATOR" content="Created by BlueVoda">
<script type="text/javascript">
<!--
function SwapImage()
{
var doc=document, args=arguments;
doc.$imgSwaps = new Array();
for(var i=2; i<args.length; i+=2)
{
var elem=FindObject(args[i]);
if(elem)
{
doc.$imgSwaps[doc.$imgSwaps.length]=elem;
elem.$src=elem.src;
elem.src=args[i+1];
}
}
}
what do you advice me to do?
thank you

faisal

navaldesign · #2 05-01-2008, 09:41 AM

You said it yourself: you need to copy and paste. Copy it from the Forms Tutorial, and Paste it in your page HTML !

Go in the Tutorial, and look BELOW the video presentation for the code AND the instructions. It is stated in the very first line that you MUST look under the video presentation.

faisal evers · #3 05-01-2008, 09:51 AM

ok thank you very much

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